shielding for AC (power, audio)?

[sandyk]

16 minutes ago, audiventory said:

DC voltage drop don't depend on ferrite or air there.

 

DC and AC voltage drops are different there.

 It does, because for the same value of inductance in larger values you need to use more turns of wire with an air core, hence extra DC resistance.

 Please take your theoretical nit picking to a thread where it may be appreciated !

 You have already managed to derail this thread .

[sandyk]

Yuri

 Are you using Google to translate ?

It appears that we DO have a language difference problem here as I suggested in an  earlier reply. .

 

Alex

 

 

[audiventory]

51 minutes ago, sandyk said:

It does, because for the same value of inductance in larger values you need to use more turns of wire with an air core, hence extra DC resistance. 

 

Length and diameter of wire, ferrite that used to coil production impact to inductance.

 

Length and diameter of this wire impact to the coil active resistance.

 

I wrote "Coil have almost zero resistance for DC".

 

You wrote "DC resistance of 160mOhms and is rated to 5A".

 

It is Udc=0.160 Ohm * 5 A = 0.8 V for DC.

 

For AC you must call amplitude of AC-pulses.

 

Because general voltage at the bus (wire) is:

 

U = Uds + Uac. (it is not complex values)

 

[audiventory]

6 minutes ago, sandyk said:

Are you using Google to translate ?

It appears that we DO have a language difference problem here as I suggested in an  earlier reply.

I use it to translate some words.

 

There is no lost translation.

[Ralf11]

21 hours ago, sandyk said:

 

 Unfortunately, the more twists in the cable the less flexible it becomes .

 

we were fine until Chubby Checkers died

[buonassi]

Sometimes I find Yuri's posts helpful as I'm not an EE and they tend to stay very 'high level'.  He normally posts links to articles.  That may be the solution?  This way he steers ignoramuses like me toward some basic info and doesn't offend more knowledgeable members.  Maybe?